Suppose, the remainder obtained while dividing x by 61 is 2. What is the remainder obtained while dividing x7 by 61?
Let the number be 63, According to the question 637/61 As we know, 63 – 61 = 2, 27/61 ⇒ 128/61 When we divide 128 by 61 we get remainder 6.
22.03 × 6.97 + 19.01 – 16.02 = ?
√440.98 + (17.95% of 249.96 – 12% of 99.99) + (7.12)2 = ?
90.004% of 9500 + 362 = ?
(80.95) (1/4) + (3.05) 3 - 119.78 × 2.15 + (14.98)2 = ?
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
(44/25) ÷ (154/199.5) × 419.91 = ? – (11.11)3
88% of 900.23 + 74.99 = ?
124% of 620.99 + 11.65% of 1279.23 = ?
?% of (128.31 ÷ 15.97 × 75.011) = 419.98
(15.98% of 399.99) - 6.998 = √?
