Question
When 135 is added to 3A7, the result is 4B2. 4B2 is
divisible by 3. What is the largest possible value of A?Solution
3A7 + 135 = 4B2Ā Clearly A+1+3 =B or A+4=B So possible values for A & B are: - A = 0, 1, 2, 3, 4, 5 & B = 4, 5, 6, 7, 8, 9Ā & 4B2 is exactly divisible by 3.Ā Now, 4 + B + 2 = 6+B = multiple of 3Ā Therefore, B = 6 or 9 is only possible values and accordingly,Ā Ā A = 2 or 5 is possible value for A, Hence largest possible value of A is 5.
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