Question
A scored 44% marks and failed by 60 marks whereas B
scored 74% marks, which was 90 more than the passing marks of the examination. Find the total marks of the examination.Solution
Let the total available marks in the examination be 100x. Marks scored by A = 44% of 100x= 44x Marks scored by B = 74% of 100x= 74x According to question, => 44x + 60 = 74x – 90 => 30x = 150 => x = 5 Total marks of the examination = 100x = 500
?3 - (77.98 ÷ 6.09 + 10.12)2 + (2.015 - 11.983)2 = 20.01 × (215.98(2/3) - √36.03)
(799.81/64) ÷ (10/799.92) × (129.84/130) = ?
...- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
? + 157.99 – 101.01 = 25.01 × 5.98
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04
33.33% of 110.99 = 19.98% × 244.97 - √?
56.05 2 – 24.24 2 + (63.98) 3/2 – 32.28% of 1500 = ? 2 + 113.03 × 5.09
766/51 ÷ 387/42 × 121/13 = ?
Solve the given equation for ?. Find the approximate value.
(124.85% of 639.77 – 39.85% of 450.21) × (√224.85 ÷ √35.96) = ?
...16.01(? × 8.09 ÷ 16.09) = 3.01 of 69.69 + 14.12 of 4.01 - 100.998 of 2.19
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