150 litres of mixture ‘A’ (milk + water) contains 36 litres more water than milk. If 50% of mixture ‘A’, 70 litres of milk and 60 litres of water are added in an empty jar, then the quantity of milk is what percentage of the quantity of water in the jar?

Solution

Let the quantity of milk in mixture ‘A’ = ‘y’ litres Then, quantity of water in mixture ‘A’ = (y + 36) litres So, y + y + 36 = 150 Or, 2y = 150 – 36 = 114 Or, y = 114/2 = 57 So, quantity of milk in mixture ‘A’ = 57 litres And, quantity of water in mixture ‘A’ = 57 + 36 = 93 litres Quantity of milk in 50% of mixture ‘A’ = 57 × 0.50 = 28.5 litres Quantity of water in 50% of mixture ‘A’ = 60 × 0.50 = 30 litres So, quantity of milk in the jar = 28.5 + 70 = 98.4 litres Quantity of water in the jar = 60 + 30 = 90 litres So, required percentage = (98.5/90) × 100 ≈ 109%