150 litres of mixture ‘A’ (milk + water) contains 36

Solution

Let the quantity of milk in mixture ‘A’ = ‘y’ litres Then, quantity of water in mixture ‘A’ = (y + 36) litres So, y + y + 36 = 150 Or, 2y = 150 – 36 = 114 Or, y = 114/2 = 57 So, quantity of milk in mixture ‘A’ = 57 litres And, quantity of water in mixture ‘A’ = 57 + 36 = 93 litres Quantity of milk in 50% of mixture ‘A’ = 57 × 0.50 = 28.5 litres Quantity of water in 50% of mixture ‘A’ = 60 × 0.50 = 30 litres So, quantity of milk in the jar = 28.5 + 70 = 98.4 litres Quantity of water in the jar = 60 + 30 = 90 litres So, required percentage = (98.5/90) × 100 ≈ 109%