Question
The product of two consecutive even integers is 960. Find
the product of digits of the bigger number.Solution
ATQ,
Let the required numbers be (n - 1) and (n + 1).
So, (n - 1) × (n + 1) = 960
Or, n² - 1 = 960
Or, n² = 961
Or, n = 31
Larger number = 31 + 1 = 32
Required product = 3 × 2 = 6
√256 * 3 – 15% of 300 + ? = 150% of 160
(5.6 + 2.4 + 13.8 – 2.8) × 5 = ? × (12.5 – 7.5)
Solve: 3/4÷2/3 ​
(292 – 141) ÷ 5 + (40 ÷ 2) + 23 = ?
(26)2 = {(20% of 40% of 18200) ÷ ?} × 1664 ÷ 128Â
- What will come in place of (?) in the given expression.
(18.5 × 2) + (3.5 × 4) = ? What will come in the place of question mark (?) in the given expression?
48 X 2.5 + 20% of 150 = ? + 166
166/? = √576 - 3.25
[(36 × 15 ÷ 96 + 19 ÷ 8) × 38] = ?% of 608