Let S be the sample space. Then, N(S) = number of ways of drawing 2 pens out of 11 = ¹¹C₂ = (11 ×10 )/(2 ×1) = 55 Let E = event of getting the one black and one red pen out of 8 pen. n(E) = ⁵C₁ × ³C₁ = 5 × 3 = 15 n(P) = (n(E))/(n(S)) = 15/55 = 3/11
{(440.89 ÷ 20.74) ÷ 2.88} × 48.65 = ? 3
657.94 + 335.21 - 211.09 - 82.30 = ?
? = 41.92% of 49.96% of (45.07 1.97 – 4.98 2.03 )
49.96% of 120.21 + √(15) ÷ 1.87 × 4.41 = ?
35.05% of 14.87 × (13.02 – ?) + 30.19 = 188.7
32.052- 22.03 x 24.199 - 15.18 x 11.04 = ?
Solve the following expression and calculate the approximate value.
118.95 – 24.10 + (91.90 ÷ 22.89 × 12.14) = ?
1254.04 – 440.18 + 399.98 ÷ 10.06 = ?
49.99% of 539.99 + 263.98% of 49.99 = ?% of 1608.01