Saket and Rakesh are brothers whose shops are located at a distance of 10km and 12km respectively from their home. Both of them start at the same time from home every day and reach their respective shops exactly at 8 am. When they decided to swap shops for a day, Saket started 4 minutes earlier than Rakesh. If both of them reached on time, what is the speed of Rakesh?
Since they cover 10km and 12km in equal time, their speeds will be in the same ratio as their distance covered. Speed =`(Distance)/(Time)` = `10/12` =`5/6` Hence, `10/(6x)+4/60=12/(5x)` `x=11` Rakesh’s speed = 66 km/hr
