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A refractometer measures the refractive index of a substance, and in the case of milk adulteration with water, the refractive index changes due to the difference in composition between milk and water. This alteration can be identified using a refractometer, making it a useful tool for detecting water adulteration in milk.
11.11% of 1800.89 + 34.89 X 10.99 - 500.50 = ?
81% of 1550 + 27² = ? + 1386 ÷ 22
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
(10.98% of 499.99) - 4.998 = √?
? = 21.08 + 18.99 × 21.07
(1120.45 ÷ 15.89) × 11.34 = ? × 4.78
(1.01) 0 + (2.02) 1 + (2.93) 2 + (4.04) 3 + (5.05) 4 = ?
35.05% of 200.05 – 20.15% of 99.99 × 3.02 = ?
(24.78 × 11.67) + (7199.67 ÷ 14.99) = ? × 12.65
