Get Started with ixamBee
Start learning 50% faster. Sign in now
CI = [6000 × (1 + 20/100)2 – 6000] = 6000 × (6/5) × (6/5) – 6000 = Rs 2640. Now SI = 1056 (i.e. 2640 × (2/5)) Therefore, (P × 4 × 16)/100 =1056 So P = Rs 1650.
For the recorded observation, the coefficient of variation is 0.2 and the variance is 16. The arithmetic mean is:
The standard error of the given data 15, 5, 12, 10, 20, 4 is
Let x and y be two variables with variance as 1990 and 796 with 11 and 9 number of observations respectively. The value of F(10, 8) at 5% level of sign...
60% of the employees of a company are college graduates. Of these, 10% are in sales. Of the employees who did not graduate from college, 80% are in sal...
Which one is not non-probability sample method
If first, second, and third moment about origin are 1, 6, and 15 respectively, then Karl Pearson beta coefficient of skewness β is
For making frequency distribution, the number of classes used depends upon:
If A and B are mutually exclusive, the general addition rule is:
Let (Xi, I ≥ 1} be independent and identically distributed random variables with P(Xi =1) = p = 1-P(Xi = 0), Sn = ∑ni = 1 X i . The dist...
For the discrete distribution, the Pearson's coefficient of skewness β2 is always:
