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      Question

      I. 2x 2 + 5x + 2 = 0 II. 4 y 2

      = 1 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;
      A if x = y Correct Answer Incorrect Answer
      B if x > y Correct Answer Incorrect Answer
      C if x < y Correct Answer Incorrect Answer
      D if x ≤ y Correct Answer Incorrect Answer

      Solution

      I. 2x2+5x+2 = 0 Pairs are 1,4 So by changing its signs & dividing by a i.e.2, we will get x = -1/2 , -2 II. 4y² = 1 y² = 1/4 y = ± 1/2 Hence, x ≤ y

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