Question
I. 3x2 - 14x + 15 = 0 II. 15 y
2 - 34 y + 15 = 0 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;Solution
I. 3x2-14x+15 = 0 Pairs are 5,9 So by changing its signs & dividing by a i.e.3, we will get x = 5/3 , 9/3 = 5/3, 3 II. 15 y² - 34 y + 15 = 0 Pairs are 9,25 So by changing its signs & dividing by a i.e.15, we will get y = 9/15 , 25/15 = 3/5, 5/3 Hence, x ≥ y
3456 1728 2592 6485 22680 102060
...299, 302, 308, 317, ?, 344
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 10Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â ...
230, 34.5, ‘?’, 0.77625
If 10 9 38 x 5428
Then, 2x² + 1 = ?
...There are two series I and II. Logic in both the series are different.
Series l: 3, 12, 28, 53, 89, .
Series II: 259, 270, 283, 300, 319.<...
12, 6, 6, 9, 18, ?
If   314     306      x      269       394    178    1480
Then, 1/3 x + 2x - x = ?
...5     16     ?      66     119      200
...9999 6666 ? 2962.66 1975.11 1316. 74
...
