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Start learning 50% faster. Sign in nowNo wire is a cable (E) + Some cables are paints (I) ⇒ Some paints are not wires (O*) All bulbs are wires (A) + No wire is a cable (E) ⇒ No bulb is a cable (E)⇒ Conversion ⇒ Some cables are not bulbs (O). All bulbs are wires (A) + No wire is a cable (E) ⇒ No bulb is a cable (E) + Some cables are paints (I) ⇒ Some paints are not bulbs (O*). Hence, option 1 is correct. By elimination method - By 2, some + some = no –ve conclusion can be drawn between bulb and cable. Hence it is eliminated. By 3, No + No = no relation can be drawn between wire and paint. Hence it is eliminated. By 4, some + some = no –ve conclusion can be drawn between paint and wire. Hence it is eliminated. Hence answer is option 1.
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