Question
Statements: Some reds are
blues. All blues are greens. Some greens are not yellows. Conclusions: I. Some yellows are reds. II. Some yellows are blues. III. Some greens are reds. In each of the questions below are given three statements followed by three conclusions numbered I, II and III. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of given conclusions logically follows from the given statements disregarding commonly known facts.Solution
Some reds are blues (I) + All blues are greens.(A) = Some reds are greens.(I) ⇒ conversion ⇒ Some greens are reds (I) Hence, conclusion III follows.
I. 14p2 – 135p + 81 = 0
II. 7q2 – 65q + 18 = 0
I. x3 = 1728
II. y2 – 15y + 56 = 0
I. 7x² + 27x + 18 = 0
II. 19y² - 27y + 8 = 0
Equation 1: x² - 250x + 15625 = 0
Equation 2: y² - 240y + 14400 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
I. 3p² + 13p + 14 = 0
II. 8q² + 26q + 21 = 0
I. x ² + 5 x + 6 = 0                Â
II. y²+ 7 y + 12= 0
...Roots of the quadratic equation 2x2 + x – 528 = 0 is
l. x2 - 16x + 64 = 0
II. y2Â = 64
If x + 1/x = 3, find x² + 1/x².