Question
Statements: No herb is a tree. Some trees are
shrubs. No shrub is petal. Conclusions: I. No petal is a shrub. II. Some shrubs are not herbs. III. No tree is a petal. In each of the questions below are given three statements followed by three conclusions numbered I, II and III. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of given conclusions logically follows from the given statements disregarding commonly known facts.Solution
No shrub is petal(E) ⇒ Conversion ⇒ No petal is a shrub(E). Hence, conclusion I follows. No herb is a tree(E) + Some trees are shrubs(I) ⇒ Some shrubs are not herbs(O*). Hence, conclusion II follows. Some trees are shrubs(I) + No shrub is petal(E) ⇒ Some trees are not petals(O). Hence, conclusion III does not follow
1.3wx = 40 – wy
2. b2 = 2b + p
3. d2 + d = q
Now, observe the given conditions:
One root of equation...
I. 63x2 + 148x + 77 = 0
II. 21y2 + 89y + 88 = 0
I. 3x2 – 17x + 10 = 0
II. y2 – 17y + 52 = 0
What is the average salary of 10 officers , if a clerk’s salary is Rs. 15,000?
Statement I: The total salary of 10 officers and 5 clerk is Rs....
The quadratic equation 2x² − kx + 3 = 0 has equal roots. Find k.
If x^2 - 7x + k = 0 has roots that are equal, what is the value of k?
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 22x + 120 = 0
Equation 2: y² - 25y + 144 = 0
I). 4p + 3q = 25
II). 5p + 2q = 26Â
I. x2 + 28x + 96 = 0
II. y2 + 3y - 70 = 0
I. 5q = 7p + 21
II. 11q + 4p + 109 = 0