Get Started with ixamBee
Start learning 50% faster. Sign in now
All meggi are momos (A) + All momos are burger (A) ⇒ All meggi are burger. Hence, conclusion I follows. All chowmin are momos (A) + All momos are burger (A) ⇒ All chowmin are burger (A) ⇒ conversion ⇒ Some chowmin are burger (I). Hence, conclusion II follows.