Statements: All Meggi are momos.
All chowmin are momos.
All momos are burger.
Conclusions:
I. All meggi are burger.
II. At least some chowmin are burger.
All meggi are momos (A) + All momos are burger (A) ⇒ All meggi are burger. Hence, conclusion I follows. All chowmin are momos (A) + All momos are burger (A) ⇒ All chowmin are burger (A) ⇒ conversion ⇒ Some chowmin are burger (I). Hence, conclusion II follows.
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