Question
Statement: All badmintons are rackets.
Some rackets are rubbers. No rubber is a string. Conclusion: I. Some strings are not rackets. II. Some rubbers may not be rackets. III. No badminton is rubber. In each of the questions below are given three statements followed by three conclusions numbered I, II and III. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of given conclusions logically follows from the given statements disregarding commonly known facts.Solution
Some rackets are rubbers(I) + No rubber is a string(E) → Some rackets are not strings(O). Hence, conclusion I will not follow. Some rackets are rubbers(I) → conversion → Some rubbers are rackets(I) → Probable conclusion → Some rubbers may not be rackets(O). Hence, conclusion II will follow. A + I = no conclusion. Hence, conclusion III will not follow.
480 ÷ 10 + 18 % of 160 + ? * 9 = 60 * √36
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(2100.23 ÷ 34.98) + (864.32 ÷ 23.9) + 1854.11 =?
- 29.98% of 249.897 = ?² – (4.98)²
What is the area (in cm²) of a square inscribed in a circle with a radius of 10√2 cm?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will replace the question mark (?) in the following?
29.99...
(363.89% of 224.98 – 319.86% of 134.94) ÷ ? = √(134.88 ÷ 15.25)