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C faces the one who sits third to the right of K. D sits fourth to the left of E. Neither C nor K sits adjacent to both D and E. Only two persons sit between D and L who sits second to the left of H. As many persons sit between H and D is the same as between C and J. So we get Two Cases
The one who sits second from J is sits second to the right of F. G sits third to the right of I.
Hence the second case gets discarded so we get the final arrangement as
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