Question
A person spends 5 times the amount he saves in a month. If
his monthly expenses are Rs. 6,000, calculate his total monthly income.Solution
ATQ,
Let the income of the person be Rs. ‘6x’
Monthly savings of the person = 6x × (1/6) = Rs. ‘x’
Expenditure of the person = 6x – x = Rs. ‘5x’
Also, 6000 = 5x
Or, x = 1200
Monthly income of the person = 1200 × 6 = Rs. 7,200.
I. 3x2Â + 3x - 60 = 0Â Â Â Â Â
II. 2y2Â - 7y + 5 = 0Â
I. 2x2 + 3x - 9 = 0
II. 3y2 - y - 10 = 0
Equation 1: x² - 120x + 3500 = 0
Equation 2: y² - 110y + 3025 = 0
I. 117x² + 250x + 117 = 0
II. 54y² -123y + 65 = 0
I.70x² - 143x + 72 = 0
II. 80 y² - 142y + 63 = 0
I. 2 x² - 15 + 18 = 0
II. x²- 3 + 2 = 0
...I. 12x2 + 22x + 8 = 0
II. 4y2 - y − 3 = 0
I. 2 x ² + x  – 1 = 0                Â
II. 2 y ² - 3 y + 1 = 0
...- What should be the value of t in the equation x² + tx + 64 = 0 so that it has two equal real roots?
I. 9/(4 )p + 7/8p = 21/12
II. 7/5p = 9/10q + 1/4