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G is taller than E. G is shorter than I and E is taller than H. I > G > E > H The number of persons taller than I is same as the number of persons shorter than H. The number of persons taller than D is one more than the number of persons shorter than F. I > G > D > E > F > H The height of the third tallest person is 180cm and the height of the shortest person is 160cm. The height of F is not 180cm. I > G > D(180) > E > F > H(160) Therefore, the final arrangement is as follows: I > G > D (180cm) > E > F > H (160cm)
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The median of the following observations 10, 11, 9, 12, 10,10, 12, 10, 9,11 is:
For the ANOVA which option is wro1ng?
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The fair dice is rolled 15 times and face value are noted
Face Value: 1 2 3...
Which one is not basis of classification of data.