If V is kept behind W, then number of boxes is kept

Solution

Z is kept ahead of X and Y.

Z X/Y Y/X

As many boxes are kept ahead of Z as behind Y.

_____ _____ Z X Y ____ ____ …… (I)

_____ Z X Y ____ …… (II)

Z X Y …… (III)


T is kept behind X but ahead of W. W is not the last box in the queue and U is not the first box in the queue. V is kept behind U and T. Only one box is not kept ahead of X.

Case I and II will get discarded.

_____ _____ Z X Y T W …… (I)

_____ Z X Y ____ …… (II)

Z U X T V/W W/V Y …… (III)

Therefore, the final arrangement is: Z U X T W/V V/W Y