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Z is kept ahead of X and Y.
Z X/Y Y/X
As many boxes are kept ahead of Z as behind Y.
_____ _____ Z X Y ____ ____ …… (I)
_____ Z X Y ____ …… (II)
Z X Y …… (III)
T is kept behind X but ahead of W. W is not the last box in the queue and U is not the first box in the queue. V is kept behind U and T. Only one box is not kept ahead of X.
Case I and II will get discarded.
_____ _____ Z X Y T W …… (I)
_____ Z X Y ____ …… (II)
Z U X T V/W W/V Y …… (III)
Therefore, the final arrangement is: Z U X T W/V V/W Y
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