If the sum of sweets in carton M and N is 88 and sum of

Solution

M + N = 88 52 + N = 88 N = 88 – 52 = 36. N + P = 66 36 + P = 66 P = 66 – 36 = 30. L will have number of sweets between 30 and 36. M has more sweets than N but less than K. L doesn’t have lowest number of sweets but less than N. N doesn’t have 4th highest number of sweets. K > M > N > L J has more sweets than P but less than O. O has more sweets than N but less than M. Carton, which has 2nd highest number of sweets, has 52 sweets. K > M (52) > O > N > J > L > P The final arrangement is as follow: K > M (52) > O > J > N > L > P