📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!


    âš¡ Azaadi sale - Celebrate Independence Day with Flat 55% Off On all courses! 13 to 17 Aug âš¡ Enroll Now

    Question

    If the sum of sweets in carton M and N is 88 and sum of

    sweets in carton N and P is 66, then what is the probable number of sweets in carton L? Answer the questions based on the information given below. Seven cartons (J, K, L, M, N, O and P) have different numbers of sweets. M has more sweets than N but less than K. J has more sweets than P but less than O. L doesn’t have lowest number of sweets but less than N. N doesn’t have 4th highest number of sweets. O has more sweets than N but less than M. Carton, which has 2nd highest number of sweets, has 52 sweets.
    A 39 Correct Answer Incorrect Answer
    B 29 Correct Answer Incorrect Answer
    C 32 Correct Answer Incorrect Answer
    D 37 Correct Answer Incorrect Answer
    E 52 Correct Answer Incorrect Answer

    Solution

    M + N = 88 52 + N = 88 N = 88 – 52 = 36. N + P = 66 36 + P = 66 P = 66 – 36 = 30. L will have number of sweets between 30 and 36. M has more sweets than N but less than K. L doesn’t have lowest number of sweets but less than N. N doesn’t have 4th highest number of sweets. K > M > N > L J has more sweets than P but less than O. O has more sweets than N but less than M. Carton, which has 2nd highest number of sweets, has 52 sweets. K > M (52) > O > N > J > L > P The final arrangement is as follow: K > M (52) > O > J > N > L > P

    Practice Next
    ask-question

    Not sure which exam is best for you Talk to our expert

    Get My Free Call