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The marks of E is more than the marks of H. The number of persons more than E is one less than the number of persons less than H. E > ___ > _____ > ___ H > ___ ……… (I) ____ > E > ___ > H > ___ > ___ ……… (II) The marks of F is more than I, whose marks is more than G. At least two persons have less marks than G. E > F > I > G > H > D ……… (I) ____ > E > ___ > H > ___ > ___ ……… (II) Case 2 will get discarded. Therefore, the final arrangement is as follow: E(highest) > F > I > G > H > D(lowest)
44.99% of 499.98 × (3.30/7.40)% of 1399.97 + 10.02 = ?
25.6% of 250 + √? = 119
∛857375 + ∛91125 = ? + √6889
26 2 – 13% of 400 + (529 ÷ 23 2 ) = ? 2
(6.013 – 20.04) = ? + 9.98% of 5399.98
20% of (√9216 + ?) = 24
(1748 ÷ 8) + 76.8 × 35 =(? × 4) + (42 × 35.5)
4387897 – 3286871 – 51926 = ?
20 ×33 + 12 × 23 - 40 ÷ 15-1 + ? = 50