Question
If the sum of the weights of U and S is 100kg then, what
can be the weight of item P? Answer the questions based on the information given below. There are six items P, Q, R, S, T and U. Each of the items has different weight. P is heavier than S but lighter than U. The weight of second heaviest item is 58kg. The weight of the second lightest item is 35kg. The weight of Q is more than the weight of S and T, which is the lightest among all. U is not the heaviest item. R is lighter than P.Solution
P is heavier than S but lighter than U. The weight of Q is more than the weight of S and T, which is the lightest among all. U is not the heaviest item. R is lighter than P. U > P > S Or Q > S > T Also, T is the lightest among all and U is not the heaviest. So, Q must be the heaviest item among all. The final arrangement is as follows: Q > U(58) > P > S/R > R/S (35) > T If the sum of the weights of U and S is 100 kg i.e., U (58) + S (42) = 100kg so, the weight of P can be 45kg.
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