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P is heavier than S but lighter than U. The weight of Q is more than the weight of S and T, which is the lightest among all. U is not the heaviest item. R is lighter than P. U > P > S Or Q > S > T Also, T is the lightest among all and U is not the heaviest. So, Q must be the heaviest item among all. The final arrangement is as follows: Q > U(58) > P > S/R > R/S (35) > T If the sum of the weights of U and S is 100 kg i.e., U (58) + S (42) = 100kg so, the weight of P can be 45kg.
X and Y are independent normal variables with mean 50 and 80 respectively and standard deviation as 4 and 3 respectively. What is the distribution o...
With reference to analysis of variance. which of the following statements is/are correct?
(I) Change of origin will affect the value of F
...If the first, fifth and ninth decile of frequency distribution xi ∣ fi are 3,10,16, respectively, then Kelly's coefficient of skewness is:
If A and B are mutually exclusive, the general addition rule is:
Which of the following approaches does multiplicative model have for the component of Time series Secular trend (7). Seasonal variation (S), Cyclical f...
If Z follows standard normal distribution with mean 0 and variance 1, then Z2 follows:
Which option is WRONG?
With which characteristic movement of a time series would you associate increasing demand of smaller automobiles?