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(i) Z lives on the fifth floor. (ii) V does not live on an odd – numbered floor and U lives below Z. Only W lives between V and U. (iii) There are three floors between the floors on which Y and W live. (iv) S lives on a prime numbered floor. There will be two cases: It is given that Z lives on the fifth floor. If V lives at floor no. 2, then W and U live at 3 and 4 respectively. Y lives at floor no. 7. If V lives at floor no. 4, then W and U live at 3 and 2 respectively. Y lives at floor no. 7. S lives at floor no. 11. (v) None of the vacant floor is an odd-numbered floor. (vi) V does not live on a floor immediately above or immediately below X’s floor. There is one vacant floor between the floors on which S and T live. (vii) The number of floors between the two vacant floors is the same as the floor number on which W lives. (viii) X lives on an odd-numbered floor. X lives below T’s floor. R lives on an even numbered floor. T lives at floor no. 9 and vacant floor is floor no.10. We know that W lives at floor no. 3. So, there will be gap of three floors between vacant floors. Other vacant floor is floor no. 6. Case 1 will get discarded as X will live at floor no. 8 but X lives on an odd-numbered floor.
Final arrangement as shown below:
19.97% of 3/5 ÷ (1 ÷ 74.99) = ?
1456.92 + ? – 1324.87 = 1875.34 – 1683.29
95.001% of 8219.99 - 4/9 % of 5399.98 + 109.99 = ?
29.98% of 549.99 = ? - 254.97 + 79.98% of 74.99
12.023 + 32.05 × 16.08 – 84.04% of 2400 = 56.06% of ?
(1550.23 ÷ 30.98) + (864.32 ÷ 23.9) + 1724.11 = ?
3374.89% of 31.80 – 1739.85% of 44.72 = (?2 )% of 1188.13
157.78% of 4820 + 92.33% of 2840 = ? + 115.55% of 1980