If ‘H’ is born between ‘B’ and ‘C’, then what can be the age of ‘H’?

Read the following information carefully and answer the questions given below. Eight persons A, B, C, D, E, F, G and H are born in four different years viz., 1964, 1977, 1982 and 1991 and also in two different months viz., June and July but not necessary in the same order. All they are wearing eight different watches namely Noise, Omega, Citizen, Casio, Tissot, Timex, Titan and Amazfit. No two persons born in same month of a year. Age of the persons is calculated as on December 2020.Each year two persons were born in two different months. Months are not considered for age calculation. The person who wears Noise born immediately before F. F was born in the month which has 30 days. The sum of the ages of B and the one who wears Omega is equal to perfect square of a number. There are only three persons born between E and the one who wears Casio. D was not born in odd numbered year. More than two persons born between H and one who wears Tissot. As many persons born between A and the one who wears Timex is same as the persons born after the one who wears Citizen. There are two persons born between D and the one who wears Titan. Age of the one who wears Casio is not a prime number but born in one of the months before the one who wears Citizen. There are only two persons born between the one who wears Casio and the one wears Omega. Only one person born between B and the one who wears Titan, who was not born in the year 1964. C and the one who wears Tissot are born in different month. A was born immediately after the F. H does not like Timex. F was not born immediately before or after the one who wear Citizen.