Get Started with ixamBee
Start learning 50% faster. Sign in now
At most two people celebrated their birthday after G. Neither F nor G celebrated their birthday on 28th of the month. The difference between the days of G and E to celebrate their birthday is 12. X celebrated his birthday immediately before E. No one celebrated their birthday between Y and F, who celebrated his birthday after Y. Z celebrated his birthday after H, who doesn’t celebrate his birthday before X. From above statements, Case-1 : Here G and E celebrated their birthday on 20th and 8th of the month respectively. X celebrated his birthday on 4th of the month. Y and F celebrated their birthday on 12th and 16th of the month respectively. Finally, H and Z celebrated their birthday on 24th and 28th of the month respectively. Thus all the given condition gets satisfied and we get the completed arrangement in Case- Case-2: Here G and E celebrated their birthday on 24th and 12th of the month respectively. X celebrated his birthday on 8th of the month. Y and F celebrated their birthday on 16th and 20th of the month respectively. As per last reference point, H doesn’t celebrate his birthday before X. Thus there is no other date left for H. Thus this case-2 becomes invalid and it can be eliminated. 
Statements: Q % R & L @ T $ D; W % Q # P
Conclusions : I. D % R II. Q % L I...
Statement:
Q < B ≥ M; M > T = V; S < J = K ≥ L; V > K
Conclusion:
I. B > S
II. B > L
III. M < J
Statement: D < E < F ≥ G; D ≥ H > I
Conclusion: I. F > I II. F = I
Statements: M % N, N & A, A @ B, B # C
Conclusions: I. C & A II. M # B
...Statements: R > S ≥ T = U < V ≤ W; X ≥ Y = Z < U = M ≥ N
Conclusions:
I. S ≥ M
II. T < X
III. W > N
Statements: P < L = O; N = M ≤ J ≤ K; M ≤ L
Conclusions:
I. K ≥ O
II. N ≤ L
III. O ≥ N
Statement: C ≥ D > E < F ≥ G; D ≥ H = J
Conclusion:
I. C > H
II. C = J
Statement: J > H ≤ G; F < M ≤ J; G = K
Conclusion: I. M ≤ G II. M > K
Statement: W > X > Y; Z > B > W; Z < C
Conclusion: I. Y < Z II. B > X
Statements:
S = K ≥ A ≥ X; Y < K = E ≤ U < Z
Conclusion:
I. X = E
II. K > X
