Question
Which two numbers should be interchanged to make the
given equation correct? 14 + 32 − 56 ÷ 28 × 5 = 40Solution
1) 14 + 32 − 56 ÷ 28 × 5 = 40 14 + 28 – 56 ÷ 32 × 5 = 40 14 + 28 – 1.75 × 5 = 40 14 + 28 – 8.75 = 40 33.25 ≠ 40 2) 14 + 32 − 56 ÷ 28 × 5 = 40 5 + 32 – 56 ÷ 28 × 14 = 40 5 + 32 – 2 × 14 = 40 5 + 32 – 28 = 40 9 ≠ 40 3) 14 + 32 − 56 ÷ 28 × 5 = 40 32 + 14 − 56 ÷ 28 × 5 = 40 32 + 14 − 2 × 5 = 40 32 + 14 – 10 = 40 36 ≠ 40 4) 14 + 32 − 56 ÷ 28 × 5 = 40 28 + 32 − 56 ÷ 14 × 5 = 40 28 + 32 – 4 x 5 = 40 28 + 32 – 20 = 40 40 = 40
The number of significant figures for 5.1250 and 0.06900 respectively are____
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