Question
Three of the following four number-clusters are alike in
a certain way and thus form a group. Which is the one that does not belong to that group?Solution
The logic here is: (1st digit) x 2 = 2nd digit; (2nd digit + 2) = 3rd digit  246 → 2 x 2 = 4; 4 + 2 = 6 124 → 1 x 2 = 2; 2 + 2 = 4 369 → 3 x 2 = 6; 6 + 2 = 8 ≠9 124 → 1 x 2 = 2; 2 + 2 = 4 Thus, the odd one out is 369. Hence, the correct answer is (C).
I. 3x6- 19x3+16=0
II. 9y4- 27y2+20=0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 2x2 – 25x + 33 = 0
II. 3y2 + 40y + 48 = 0
I. 6x2 + 23x + 10 = 0
II. 2y2 - 3y - 5 = 0
I. (x13/5 ÷7) = 5488 ÷ x7/5
II. (y2/3 × y2/3 ) ÷ √4 = (343y)1/3...
I: 2x² - 8x + 6 = 0
II: 3y² - 12y + 9 = 0
I. 64x2 - 64x + 15 Â = 0 Â Â Â Â
II. 21y2 - 13y + 2Â =0
The quadratic equation (p + 1)x 2 - 8(p + 1)x + 8(p + 16) = 0 (where p ≠-1) has equal roots. find the value of p.
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
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