Question
Four letter-clusters have been given, out of which three
are alike in some manner and one is different. Select the letter-cluster that is different.Solution
The logic followed here is:  Positional value of 1st alphabet – 2, 2nd alphabet – 4, and 3rd alphabet – 6.  SQMG = S (19) – 2 = Q (17) – 4 = M (13) – 6 = G (7)  NLHC = N (14) – 2 = L (12) – 4 = H (8) – 5 = C (3)  XVRL = X (24) – 2 = V (22) – 4 = R (18) – 6 = L (12)  QOKE = Q (17) – 2 = O (15) – 4 = K (11) – 6 = E (5)  Hence, the correct answer is (B).
tan 20Ëš x tan 23Ëš x tan 67Ëš x tan 70Ëš = ?
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2(sin² 15° + sin² 75°) + 4sin 30° - (2sec 60° + cot 45°)
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...If sin α + cos β = 2 (0˚ ≤ β < α ≤ 90˚), then sin[(2α + β)/3] =?
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