If first and last digit of each number is multiplied and then the product is added to the sum of the middle two digits of the number, which resultant number is obtained more than once?
5268 = 5 × 8 + 2 + 6 = 48 4664 = 4× 4 + 6 + 6 = 28 2976 = 2 × 6 + 9 + 7 = 28 1459 = 1 × 9 + 4 + 5 = 18
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