Question
If first and last digit of each number is multiplied and
then the product is added to the sum of the middle two digits of the number, which resultant number is obtained more than once? These questions are based on the following set of numbers: 5268 4664 2976 1459 4397Solution
5268 = 5 × 8 + 2 + 6 = 48 4664 = 4 × 4 + 6 + 6 = 28 2976 = 2 × 6 + 9 + 7 = 28 1459 = 1 × 9 + 4 + 5 = 18
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