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    Question

    Which two digits and signs can be interchanged so as to

    balance the given equation? 328 - 82 + 120 X 6 ÷ 41 = 646
    A 82 and 6, - and ÷ Correct Answer Incorrect Answer
    B 82 and 41, - and ÷ Correct Answer Incorrect Answer
    C 82 and 41, ÷ and X Correct Answer Incorrect Answer
    D 6 and 120, + and ÷ Correct Answer Incorrect Answer

    Solution

    Given Equation: 328 - 82 + 120 X 6 ÷ 41 = 646 Interchanging the digits and signs given in option 'a', we get: 328 ÷ 6 + 120 X 82 - 41 = 646 LHS = 328 ÷ 6 + 120 X 82 - 41 Cannot be determined as '328' is not completely divisible by '6'. Interchanging the digits and signs given in option 'b', we get: 328 ÷ 41 + 120 X 6 - 82 = 646 LHS = 8 + 120 X 6 - 82 = 8 + 720 - 82 = 728 - 82 = 646 646 = 646 LHS = RHS Interchanging the digits and signs given in option 'c', we get: 328 - 41 + 120 ÷ 6 X 82 = 646 LHS = 328 - 41 + 120 ÷ 6 X 82 = 328 - 41 + 20 X 82 = 328 - 41 + 1640 = 1968 - 41 = 1927 1927 ≠ 646 LHS ≠ RHS Interchanging the digits and signs given in option 'd', we get: 328 - 82 ÷ 6 X 120 + 41 = 646 LHS = 328 - 82 ÷ 6 X 120 + 41 = 328 - 1640 + 41 = 369 - 1640 = -1271 -1271 ≠ 646 LHS ≠ RHS So, only after interchanging the digits and signs given in option 'b', we can get a balanced equation. Hence, option b.

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