Question
If in the number '4735267843', '1' is added to all the
odd digits and '2' is subtracted from the all the even digits then, all the digits are arranged in ascending order from left to right. What is the sum of last four digits from the right end of the number thus formed?Solution
4Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 3 2Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 2Â Â Â Â Â Â Â Â Â 4 0Â Â Â Â Â 2Â Â Â Â Â Â 2Â Â Â Â Â 4Â Â Â Â Â 4Â Â Â Â Â Â 4Â Â Â Â Â 6Â Â Â Â Â 6Â Â Â Â Â 8Â Â Â Â Â 8 So, the sum of the last four digits from the right end is = (0 + 2 + 2 + 4) = 8.
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