Question
If all the digits of the number ' 879593548378 ' are
arranged in descending order from the left end, then what will be the sum of 2nd, 6th and 8th digit from the left end after the rearrangement?Solution
8Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 9Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 9Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 8 9Â Â Â Â Â Â Â Â Â 9Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 3 Sum of 2nd, 6th and 8th digit from the right end = 9 + 7 + 5 = 21 .
Simplify the following Boolean expression using Boolean algebra laws:
F = (A + B) * (A' + C) * (B + C)
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