Question
If the consonants of the following words are arranged
first, followed by the vowels as per the English alphabetical order and then the consonants are changed to the previous letter and the vowels are changed to the next letter in the English alphabetical series, then what will be the third letter from the right end of each of the words after the rearrangement? I. GAVE II. HOPEÂ III. HAVESolution
I. GAVE II. HOPE III. HAVE After arranging the consonants first followed by vowels as per the English alphabetical order, we get: I.  GVAE   II. HPEO   III. HVAE After changing the consonants to the previous letter and the vowels to the next letter in the English alphabetical series, we get:  I. FUBF II. GOFP III. GUBF The third letter from the right end of each of the words is: I. FUBF: U II. GOFP: O III. GUBF: U
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 20x + 96 = 0
Equation 2: y² - 18y + 72 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 21x² - 82x + 80 = 0
Equation 2: 23y² - 132y + 85 = 0
I. x=  √(20+ √(20+ √(20+ √(20…………….∞)) ) )Â
II. y= √(5√(5√(5√(5……….∞)) ) )Â
...I. 10x2 + 33x + 9 = 0
II. 2y2 + 13y + 21 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
I. 2x2 – 19x + 45 = 0
II. y2 – 14y + 48 = 0
I. 104x² + 9x - 35 = 0
II. 72y² - 85y + 25 = 0
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