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The first letter is changed to the immediate succeeding letter, the second letter is changed to the second preceding letter, the third letter is changed to the third succeeding letter, the fourth letter is changed to the fourth preceding letter and so on as per the English alphabetical series. L + 1 = M A – 2 = Y P + 3 = S S – 4 = O E + 5 = J So, code for ‘LAPSE’ is ‘MYSOJ’. D + 1 = E E – 2 = C F + 3 = I I – 4 = E N + 5 = S E – 6 = Y So, code for ‘DEFINE’ is ‘ECIESY’. F + 1 = G I – 2 = G N + 3 = Q A – 4 = W L + 5 = Q So, code for ‘ FINAL ’ is ‘ GGQWQ ’.
If cos²α + cos²β = 2, then the value of tan⁴α + sin⁸β is
(cos5°+sin5°)/(cos5°-sin5°) is equal to:
What is the value of 1/(1+tan 2θ ) + 1 / (1+cot 2 θ ) = ?
...∆ PQR is right-angled at Q. If ∠R = 60º, then find the value of cosec P.
If cot2A = tan(A+6˚ ) , find the value of A? Given that 2A and A+6˚ are acute angles.
Find the value of tan(75°) using the identity for tan(A+B).