Question
If it was Sunday on 1st September, 2013, then what was
the day of the week on 1st September, 2021?Solution
We know that: The number of odd days in a non-leap year is '1'. The number of odd days in a leap year is '2'. 2016 and 2020 are two leap years between 2013 and 2021. So, the number of odd days from 1st September, 2013 to 1st September, 2021 = (1 + 1 + 2 + 1 + 1 + 1 + 2 + 1) days = 10 days The number of days from 1st September, 2013 to 1st September, 2021 = 10 days The days of the week repeat itself after 7 days, so, (10÷7) , we get 3 as remainder. So, the number of odd days = 3 As, it was Sunday on 1st September, 2013, so, it was Wednesday on 1st September, 2021. Hence, option d.
- What will come in the place of question mark (?) in the given expression?
389 + 641 - ? = 180 X 2 - Simplify:
√529 * 5 – 15% of 220 + ? = 120% of 160
[(120)2 ÷24 ×25] ÷ 250 =?
17.6% of 250 + √? = 70% of 90
{(522 – 482 ) ÷ (27 + 73)} × 35 = ?% of 17
√1936 + √3025 = ? % of 220
√ 225 x 24 - √ 144 x 18 = ?
What will come in the place of question mark (?) in the given expression?
(40/25) X 80 - ? = 45% of 300 - 55(22% of 1500 + 15% of 2200) = ? x 11
Relevant for Exams:
