Question
What was the day of the week on ‘2nd July
2003’?Solution
Date: 2nd July 2003
Steps to find the day of the week:
Total = (3 + 0 + 0 + 2) = 5
And 5 ÷ 7, we get 5 as remainder.
Note:
Year < 2000 – leave the remainder as it is
Year > 2000 – subtract 1 from the remainder.
So, code for the day is (5 – 1) = 4
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I C has only two kids A & B and is father-in-law of D who is brother-in-law of B
II R is brother-in-law of A ...
Statements: M = U, U = V, V < W
Conclusion: I. W > M II. W = U
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