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Let the total work be 25 units (LCM of 12.5 and 25)
Efficiency of 'A' = (25/12.5) = 2 units/day
Efficiency of 'B' = (25/25) = 1 unit/day
Work done by them in first 2 days = 1 + 2 = 3 units
Work done by them in first 16 days = 3 X 8 = 24 units
Remaining work = 25 - 24 = 1 unit
Time taken by 'B' to complete remaining work = (1/1) = 1 day
Therefore, required time = 16 + 1 = 17 days
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