Question
Worker 'A' can complete the entire task alone in 12.5
days, while worker 'B' can finish it in 25 days. If they take turns working on the task each day, with 'B' starting on the first day, how many days will it take for them to complete the work together?Solution
Let the total work be 25 units (LCM of 12.5 and 25)
Efficiency of 'A' = (25/12.5) = 2 units/day
Efficiency of 'B' = (25/25) = 1 unit/day
Work done by them in first 2 days = 1 + 2 = 3 units
Work done by them in first 16 days = 3 X 8 = 24 units
Remaining work = 25 - 24 = 1 unit
Time taken by 'B' to complete remaining work = (1/1) = 1 day
Therefore, required time = 16 + 1 = 17 days
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