Question
Find the LCM of x2Â - 3x + 2 and
x2Â - 5x + 6Solution
x2Â - 3x + 2 = x2Â - x - 2x + 2 = x (x - 1) - 2(x - 1) = (x - 2) (x - 1)x2Â - 5x + 6 = x2Â - 3x - 2x + 6 = x (x - 3) - 2(x - 3) = (x - 2) (x - 3) So, required LCM = (x - 2) (x - 1) (x - 3)
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