Question
The square of a number is reduced by 26 times the
number, and then 169 is added to the result. If the final value is 0, what is the number?Solution
Let the number = 'x'According to the question,(x2Â - 26x) + 169 = 0Or, x2Â - 13x - 13x + 169 = 0Or, x(x - 13) - 13(x - 13) = 0Or, (x - 13)(x - 13) = 0So, the required number 'x' = 13
19.912 - (599.98 - 96.01 ÷ 3.01) ÷ 1.98 = ? + √254
185.92 ÷ 5.98 - (4.002)2 + 114.03 of 5.03 ÷ 18.99 of 6.04 = 5.01 of 2.99 + ? ÷ 12.02
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12.05% of 1399. 93 + 24.95 × 15.05 - 319.04 = ?Â
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