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    Question

    The square of a number is reduced by 26 times the

    number, and then 169 is added to the result. If the final value is 0, what is the number?
    A 16 Correct Answer Incorrect Answer
    B 11 Correct Answer Incorrect Answer
    C 13 Correct Answer Incorrect Answer
    D 15 Correct Answer Incorrect Answer

    Solution

    Let the number = 'x'According to the question,(x2┬а- 26x) + 169 = 0Or, x2┬а- 13x - 13x + 169 = 0Or, x(x - 13) - 13(x - 13) = 0Or, (x - 13)(x - 13) = 0So, the required number 'x' = 13

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