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      Question

      The square of a number is reduced by 26 times the

      number, and then 169 is added to the result. If the final value is 0, what is the number?
      A 16 Correct Answer Incorrect Answer
      B 11 Correct Answer Incorrect Answer
      C 13 Correct Answer Incorrect Answer
      D 15 Correct Answer Incorrect Answer

      Solution

      Let the number = 'x'According to the question,(x2 - 26x) + 169 = 0Or, x2 - 13x - 13x + 169 = 0Or, x(x - 13) - 13(x - 13) = 0Or, (x - 13)(x - 13) = 0So, the required number 'x' = 13

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