Question
The square of a number is reduced by 26 times the
number, and then 169 is added to the result. If the final value is 0, what is the number?Solution
Let the number = 'x'According to the question,(x2 - 26x) + 169 = 0Or, x2 - 13x - 13x + 169 = 0Or, x(x - 13) - 13(x - 13) = 0Or, (x - 13)(x - 13) = 0So, the required number 'x' = 13
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