Question
A and B are travelling towards each other with a speed
of 40 km/hr and 50 km/hr. If they started at same time and A covered 20 km less distance than B before meeting him, then find the distance between them before starting.Solution
Since, the time taken by A and B is same, therefore the ratio of the distance covered by them will be equal to the ratio of their speeds. Therefore, ratio of the distance covered by A and B = 40:50 = 4:5 Let the distance covered by A and B be 4x km and 5x km According to the question, 5x – 4x = 20 Or, x = 20 Therefore, distance between them before starting = 5x + 4x = 9x = 180 km
If x = 8.15, y = 9.06 and z = –17.21, then the value of x³ + y³ + z³ – 3xyz is:
Atul has Rs.500 with him. He invested 30% of the amount at 5% p.a. for 6 years and rest at 20% p.a. for 4 years. Find the sum of simple interests receiv...
 If x, y and z are real numbers such that (x-5)2+(y-8)2+(z-12)2= 0 then (x+y+z) is equal to
If x = 35, then the value of x5 - 36x4 + 36x3 - 36x2 + 36x - 1 is
If 3y-3/y=18 then find the value of y² +1/y²
 + Rs. 25200 is invested in 3 parts in such a way that Simple Interest on 1st Part at 4% per annum for 3 years, Simple Interest on 2nd
If 8x3Â - 125y3Â = (2x - Ay) X (Bx2Â + 25y2Â + Cxy), then find the value of 3 X (2A + 6B) - 2C.
What will come in the place of question mark (?) in the given expression?
(360 ÷ 24 + 105)% of ? = 48
