Question
A pipe can fill an empty cistern in 36(4/11) minutes
when working alone. However, due to a leak, it takes 50 minutes to fill the same cistern. Find the time it takes for the leak to empty 30% of the cistern on its own.Solution
Let the capacity of the tank = L.C.M of 36(4/11)Â and 50 = 400 units Then, efficiency of the pipe alone = 400 Ă· 36(4/11)Â = 400 Ă· (400/11) = 11 units/minute Combined efficiency of the pipe and the leakage = 400 Ă· 50 = 8 units/minute So, efficiency of the leak alone = 8 - 11 = 3 units/minute (outlet) 30% of the cistern = 400 X 0.3 = 120 units Time taken by the leak alone to empty 30% of the cistern = 120 Ă· 3 = 40 minutes
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