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Let the capacity of the tank = L.C.M of 36(4/11) and 50 = 400 units Then, efficiency of the pipe alone = 400 ÷ 36(4/11) = 400 ÷ (400/11) = 11 units/minute Combined efficiency of the pipe and the leakage = 400 ÷ 50 = 8 units/minute So, efficiency of the leak alone = 8 - 11 = 3 units/minute (outlet) 30% of the cistern = 400 X 0.3 = 120 units Time taken by the leak alone to empty 30% of the cistern = 120 ÷ 3 = 40 minutes
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 88x + 100 = 0
Equation 2: 17y² - 79y + 9...
I. 2p2 - 3p – 2 = 0 II. 2q2 - 11q + 15 = 0
I. 2x² + 11 x + 15 = 0
II. 2y² - 19 y + 44 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 25x² - 165x + 270 = 0
Equation 2: 27y² - 181y + ...
I. 7x + 8y = 36
II. 3x + 4y = 14
I). p2 - 26p + 165 = 0
II). q2 + 8q - 153 = 0
I. 27x² + 120x + 77 = 0
II. 56y² + 117y + 36 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
I. x2 – 13x + 40 = 0
II. 2y2 – 15y + 13 = 0