Question
The area of a square is 625 cm2 which is 40
cm2 less than that of a rectangle. Find the perimeter of the rectangle if the length of the rectangle is 10 cm more than the length of each side of the square.Solution
Area of the square = 625 cm2 Length of each side of the square = √625 = 25 cm Area of the rectangle = 625 + 40 = 665 cm2 Length of the rectangle = 10 + 25 = 35 cm So, area of rectangle = length × breadth = 35 × breadth = 665 cm2 So, breadth of the rectangle = 665/35 = 19 cm Therefore, perimeter of the rectangle = 2 × (length +breadth) = 2 × (19 + 35) = 108 cm
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