Select the set in which the numbers are related in the same way as are the numbers of the following set.
(9, 11, 40)
(15, 7, 176)

The logic followed here is: In each set, the absolute difference between the square of the 1st and 2nd number is the 3rd number. i.e., in (A, B, C) : C = |B² - A²|

In (9, 11, 40) = |11² - 9²| = |121 - 81| = 40

In (15, 7, 176) = |15² - 7²| = |225 - 49| = 176

In option '1', (8, 10, 38) = |10² - 8²| = |100 - 64| = 36 ≠ 38

In option '2', (13, 5, 140) = |13² - 5²| = |169 - 25| = 144 ≠ 140

In option '3', (6, 4, 20) = |6² - 4²| = |36 - 16| = 20

In option '4', (12, 11, 26) = |12² - 11²| = |144 - 121| = 23 ≠ 26