Question
There are eight cars A, B, C, D, E, F, G and H. Each
car has a different price. Price of C is more than that of A and D. Price of atleast two cars is less than A. Price of F is more than that of G and H. Price of D is less than G, but more than E. Price of B is less than H, but more than G. Price of atleast four cars is more than that of C. Which of the following sequence is correct?Solution
We have, Price of C is more than that of A and D, Price of at least two cars is less than A, Price of F is more than that of G and H. Price of D is less than G but more than E. Price of B is less than H but more than G. Price of at least four cars is more than that of C. So the final arrangement – F>H>B>G>C>A>D>E
Statements: H = U < S ≤ V > F = E > J ≥ I
Conclusion
I: H < F
II: V > I
Statements: S > T ≥ U ≥ V; W < X = V > Y
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