Question
Find the wrong number in the given number series.
3, 4, 10, 33, 136, 680Solution
3 X 1 + 1 = 4 4 X 2 + 2 = 10 10 X 3 + 3 = 33 33 X 4 + 4 = 136 136 X 5 + 5 = 685 Therefore, 685 should come in place of 680
If a + b = 56 and (a – b)² = 496, find the value of the product of a and b.
In △ ABC, AB = AC. A circle drawn through B touches AC at D and intersect AB at P. If D is the midpoint of AC and AP = 2.5 cm, then AB is equal to:
1/3 + 1/15 + 1/35 + 1/63 + 1/99 = ?
If [8(x + y)3 – 27(x – y)3] ÷ (5y – x) = Ax2 + Bxy + Cy2, then the value of (A2 - 2B + 3C)...
A company’s expenditure on three departments over four years is as follows (in thousands):
If 10x2 – 6xy+y² – 4x+4= 0, then find the value of (3x+2y).
Find the 36th term of the series 25, 29, 33……
If √e + (1/√e) = 10, then find the value of e + (1/e).
- If n = 5 + √6, then find the value of (n + 1/n)².
- If (u + v) = 11 and uv = 24, then find the value of (u² + v²).