Question
191 341 221 331 251
281 In each of these questions, a number series is given. In each series, only one number is wrong. Find out the wrong number.Solution
191 + (15 × 10) = 341 341 – (15 × 8) = 221 221 + (15 × 6) = 311 311 – (15 × 4) = 251 251 + (15 × 2) = 281
More Wrong Series Questions
I. x2 + 11x + 30 = 0
II. y2 + 17y + 72 = 0
I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
I. 27x6 - 152x3 + 125 = 0
II. 216y6 - 91y3 + 8 = 0
I. y² + y – 56 = 0
II. 2x² + 11 x – 40 = 0
I. 12x2 + 22x + 8 = 0
II. 4y2 - y − 3 = 0
Equation 1: x² - 250x + 15625 = 0
Equation 2: y² - 240y + 14400 = 0
I. 3x² - 22 x + 40 = 0 Â
II. 4y² + 22y + 24 = 0  Â
I). p2 + 17p - 234 = 0
II). q2 - 21q + 108 = 0
- If the quadratic equation x² + 18x + n = 0 has real and equal roots, what is the value of n?
I. 8y2 - 2y - 21 = 0
II. 2x2 + x - 6 = 0
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