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    Question

    Unit digit of a three digit number is 2 more than its

    tenth digit. If 311 is subtracted from number, then, the number obtained is 13. Find sum of digits of the original number.
    A 18 Correct Answer Incorrect Answer
    B 12 Correct Answer Incorrect Answer
    C 9 Correct Answer Incorrect Answer
    D 20 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the three-digit number be 100a+10b+c. Given: c = b+2 and (100a+10b+c)−311 = 13. Simplify:100a+10b+c = 324. Using c=b+2:100a+11b+2 = 324 ⟹ 100a+11b=322. Try a=3:100×3+11b = 322 ⟹ b=2. c=b+2=4. The original number is 324. Sum of digits: 3+2+4=9.

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