Question
Find the value of the given trigonometric
expression: (sin 15°cos 75° + cos²15°) × sin 30° + (cos 60°tan 45°) × sec 60°Solution
(sin 15°cos 75° + cos²15°) × sin 30° + (cos 60°tan 45°) × sec 60° = {sin 15°cos (90° – 15°) + cos²15°} × sin 30° + cos 60°tan 45°sec 60° Using, cos (90° – A) = sin A = (sin²15° + cos²15°) sin 30° + cos 60°tan45°sec 60° Using, sin²A + cos²A = 1 = {1 × (1/2)} + {(1/2) × 1 × 2} = (1/2) + 1 = (3/2)
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