Question
Find the value of the given trigonometric
expression: (sin 15°cos 75° + cos²15°) × sin 30° + (cos 60°tan 45°) × sec 60°Solution
(sin 15°cos 75° + cos²15°) × sin 30° + (cos 60°tan 45°) × sec 60° = {sin 15°cos (90° – 15°) + cos²15°} × sin 30° + cos 60°tan 45°sec 60° Using, cos (90° – A) = sin A = (sin²15° + cos²15°) sin 30° + cos 60°tan45°sec 60° Using, sin²A + cos²A = 1 = {1 × (1/2)} + {(1/2) × 1 × 2} = (1/2) + 1 = (3/2)
More Trigonometry Questions
Find the wrong number in the given number series.
630, 180, 60, 24, 12, 8, 5Find the wrong number in given number series.
2372, 2356, 2320, 2256, 2156, 2048.
26, 38, 60, 110, 206, 398
33 34 37 42 48 58
139, 152, 172, 205, 249, 304
2Â Â Â Â Â 4Â Â Â Â Â Â 11Â Â Â Â Â 37 Â Â Â Â Â Â 150 Â Â Â Â Â Â Â 771
...A-5,  A,  35,  52, 78, 115
132, 130, 136, 126, 142, 110
1116, 1135, 1158, 1187, 1224, 1278.
- Find the wrong number in the given number series.
7, 16, 43, 128, 367, 1096
Relevant for Exams:
