Question
Find the value of the given trigonometric
expression: (sin 22°cos 68° + cos²22°) × sin 30° + (cos 60°tan 45°) × sec 60°Solution
(sin 22°cos 68° + cos²22°) × sin 30° + (cos 60°tan 45°) × sec 60° = {sin 22°cos (90° – 22°) + cos²22°} × sin 30° + cos 60°tan 45°sec 60° Using, cos (90° – A) = sin A = (sin²22° + cos²22°) sin 30° + cos 60°tan45°sec 60° Using, sin²A + cos²A = 1 = {1 × (1/2)} + {(1/2) × 1 × 2} = (1/2) + 1 = (3/2)
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